And in order to keep it placedĭown, I have to put some rocks on top. Is, is if the system is in equilibrium, if everything You what the volume, or the pressure, or the temperature Some temperature that it starts off with. System I have a bunch of molecules or atoms bouncingĪround, creating some type of pressure on the system. So hopefully it'llīe productive for you and your school work. System that I keep using over and over again.
However, in isothermal, the temperature does not change because heat is added from the surroundings to counteract the temperature drop from the expansion. It is different because the temperature of the adiabatic system does change because the temp must go down in expansion because no heat(Q) is added. If temperature goes down, then internal energy (kinetic energy of particles) also goes down which is shown from the negative work, work out. If you remove pebbles and it expands, the temperature will go down because no heat is added. This gives you the negative work (or Wout). delta U=(3/2)nR(delta T), delta T is 0, so the right side is equal to zero because you are multiplying the (3/2)nR by 0. For the temperature to stay the same we must have some Qin to counterbalance the decrease in temperature from removing the "pebbles." Thus change in temp, delta T=0, thus delta U must be 0. For an ideal gas, internal energy is only dependent on temperature, and if the temperature does not change, then the change in internal energy is zero.
In an adiabatic process (as he states)is isolated from the world.
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